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A simple pendulum performs S.H.M. about x = 0 with an amplitude a and time period T. What is the speed of the pendulum at x = a/2? |
Answer» Speed of pendulum, \(v = \omega\sqrt{a^2 \,-\,x^2}\) \(v=\frac{2\pi}{T}\sqrt{a^2-\frac{a^2}{4}}\) = \(\frac{\sqrt3a\pi}{T}\) |
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