A sine wave has an amplitude A and wavelength `lambda`. Let V be the wave velocity and v be the maximum velocity of a particle in the medium. ThenA. V = v if `lambda = (3A)/(2pi)`B. `V= v` if `A = 2pi lambda`C. `V = v` if `A = (lambda)/(2pi)`D. V can not be equal to v

A sine wave has an amplitude A and wavelength `lambda`. Let V be the w

1.	A sine wave has an amplitude A and wavelength `lambda`. Let V be the wave velocity and v be the maximum velocity of a particle in the medium. ThenA. V = v if `lambda = (3A)/(2pi)`B. `V= v` if `A = 2pi lambda`C. `V = v` if `A = (lambda)/(2pi)`D. V can not be equal to v
Answer» Correct Answer - C

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A sine wave has an amplitude A and wavelength `lambda`. Let V be the wave velocity and v be the maximum velocity of a particle in the medium. ThenA. V = v if `lambda = (3A)/(2pi)`B. `V= v` if `A = 2pi lambda`C. `V = v` if `A = (lambda)/(2pi)`D. V can not be equal to v

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