1.

A single conservative `f_((x))` acts on a `m = 1 kg` particle moving along the x-axis. The potential energy `U_((x))` is given by : `U_((x)) = 20 + (x - 2)^(2)` where x is in metres. At `x = 5 m`, a particle has kintetic energy of 20 J The least value of x (position of particle is ) will be:A. zeroB. `-2`C. `- sqrt(29) + 2`D. `sqrt(29) + 2`

Answer» Correct Answer - C::D


Discussion

No Comment Found

Related InterviewSolutions