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A single electron system has ionization energy 11180 kJ mol^(-1). Find the number of protons in the nucleus of the system.

Answer» <html><body><p><br/></p>Solution :`IE=(Z^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))/(<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>^(2))xx21.69xx10^(-19)<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>` <br/> `(11180xx10^(3))/(6.023xx10^(23))=(Z^(2))/(1^(2))xx21.69xx10^(-19)` <br/> `Z~~3`.</body></html>


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