A single electron system has ionization energy 11180 kJ mol^(-1). Find the number of protons in the nucleus of the system.

A single electron system has ionization energy 11180 kJ mol^(-1). Find

1.	A single electron system has ionization energy 11180 kJ mol^(-1). Find the number of protons in the nucleus of the system.
Answer» Solution :`IE=(Z^(2))/(N^(2))xx21.69xx10^(-19)J` `(11180xx10^(3))/(6.023xx10^(23))=(Z^(2))/(1^(2))xx21.69xx10^(-19)` `Z~~3`.