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A single slit Fraunhofer diffraction pattern is formed with white light. For what wavelength of light the third secondary maximum in the diffraction pattern coincides with the secondary maximum in the pattern for red light of wavelength 6500 Å ?A. 4400 ÅB. 4100 ÅC. 4642.8 ÅD. 9100 Å |
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Answer» Correct Answer - C Distance of nth secondary maxima from central maxima `x=((2n+1)lambdaD)/(2a)` For red light, `x=((4+1)D)/(2a)xx6500` For unknown of light, `x=((6+1)D)/(2a)xx lambda` According to the question, `5xx6500=7xx lambda` Wavelength of light `lambda=(5)/(7)xx6500=4642.8` Å |
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