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The distance between the first and the sixth minima in the diffraction pattern of a single slit is 0.5 mm. The screen is 0.5 m away from the slit. If the wavelength of light used is 5000 Å. Then the slit width will beA. 5 mmB. 2.5 mmC. 1.25 mmD. 1.0 mm |
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Answer» Correct Answer - B Distance between first and sixth minima `x=(5lambdaD)/(d)` `therefore d=(5lambdaD)/(x)=(5xx5000xx10^(-10)xx0.5)/(0.5xx10^(-3))` `d=2.5xx10^(-3)m=2.5mm` |
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