1.

A siren placed at a railway platformis emitting sound of frequency 5 KHz. A passenger sitting in a moving train A records a frequency of 5.5KHz while the train approaches the siren . During his return journey in a different train B he records a frequency of 6.0 KHz while approaching the same siren . what is the ration of velocity of train B to that of train A ?

Answer»

Solution :Let , ` u_(A) ` be the velocity of train A .
` therefore ` Frequency of siren relative to the PASSENGER of train A ,
` n_(1) = n((V + u_(A))/(V))`
` therefore ` 5((V _ u_(A))/(V)) = 5.5 ` …(1)
Similarly , frequency of siren relative to the passenger of train B .
` n_(2) = n((V + u_(B))/(V)) [ u_(B) `= velocity of train B]
` therefore5 ((V + u_(G))/(V))= 6 ` ...(2)
From equation (1) , 5.5V -5V = 5u_(A) `
therefore V= (5)/(0.5 )u_(A)` ...(3)
` From equation (2) . 6V - 5V = 5u_(g)`
` therefore V = 5u_(g)` ...(4)
COMPARING equation (3) and (4) , ` (5)/(0.5) u_(A) = 5u_(g)`
` (u_(B))/(u_(A)) = (1)/(0.5) = 2/1therefore u_(B) : u_(A) = 2: 1 ` .


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