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A six faced ordinary cubical die marked with alphabets A, B, C, D, E, F is thrown ‘n’ times and the totalnumber of ways in which among the alphabets A, B, C, D, E and F only three of them appear in the list is10800. Then n is equal to

Answer» A six faced ordinary cubical die marked with alphabets A, B, C, D, E, F is thrown ‘n’ times and the total
number of ways in which among the alphabets A, B, C, D, E and F only three of them appear in the list is
10800. Then n is equal to


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