A slab of material of dielectric constant K has the same area as the plates of a parallel plate capacitor, but has a thickness `3d//4`. Find the ratio of the capacitanace with dielectric inside it to its capacitance without the dielectric.

A slab of material of dielectric constant K has the same area as the p

1.	A slab of material of dielectric constant K has the same area as the plates of a parallel plate capacitor, but has a thickness `3d//4`. Find the ratio of the capacitanace with dielectric inside it to its capacitance without the dielectric.
Answer» Without the dielectric, capacity of the capcitor `= C_(0) = (in_(0) A)/(d)` With dielectric of thickness `t = 3d//4`, the capacity of condenser becomes `C = (in_(0) A)/(d -t (1- (1)/(K)))` `C = (in_(0) A)/(d - (3d)/(4) (1- (1)/(K))) = (in_(0) A)/((d)/(4) (1 + (3)/(K)))` `:. (C )/(C_(0)) = (4)/(1 + (3)/(K)) =(4K)/((K + 3))`

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A slab of material of dielectric constant K has the same area as the plates of a parallel plate capacitor, but has a thickness `3d//4`. Find the ratio of the capacitanace with dielectric inside it to its capacitance without the dielectric.

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