1.

A slow neutron strikes a nucleus of `._(92)U^(235)` splitting it into lighter nuclei of barium and krypton and releasing three neutrons. Write the corresponding nuclear reaction. Also calculate the energy released on this reaction Given `m(._(92)U^(235))=235.043933 "amu" m(._(0)n^(1))=1.008665` amu `m(._(56)Ba^(141))=140.917700 "amu" m(._(36)Kr^(92))=91.895400` amu

Answer» Correct Answer - `198.77` MeV


Discussion

No Comment Found