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A small air bubble in a glass sphere of radius `2 cm` appears to be `1 cm` from the surface when looked at, along a diameter. If the refractive index of glass is `1.5`, find the true position of the air bubble. . |
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Answer» Correct Answer - `1.2 cm` Here, `mu_1 = 1, mu_2 = 1.5, R = -2 cm` Incident ray `OA` in glass is refracted in air, along `AB`, and appears to come from `I` `u = PO = ? B = PI = -1 cm` As refractive occurs from denser to rarer medium, `:. -(mu_2)/(u) + (mu_1)/(v) = (mu_1 - mu_2)/( R)` `-(1.5)/(u)+(1)/(-1) = (1 - 1.5)/(-2) = (1)/(4)` `(1.5)/(u) = - 1- (1)/(4) = -(5)/(4)` `u = (-4 xx 1.5)/(5) = -1.2 cm` The air bubble `O` lies at `1.2 cm` from the refracting surface within the sphere. |
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