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A small air bubble of radius r in water is at a depth h below the water surface. If p0 is the atmospheric pressure, ρ is the density of water and T is the surface tension of water, what is the pressure inside the bubble? |
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Answer» The absolute pressure within the liquid at a depth h is p = p0 + ρgh. Since the excess pressure inside a bubble is \(\frac{2T}R\), the pressure inside the bubble is Pin = p + \(\frac{2T}R\) = p0 + ρgh.+ \(\frac{2T}R\) |
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