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A small ball if mass `2 xx 10^(-3) Kg` having a charges of ` 1 mu C` is suspended by a string of length ` 0. 8 m` Another identical ball having the same charge is kept at the point of suspension . Determine the minimum horizontal velocity which should be imparted to the lower ball so that it can make complete revolution . |
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Answer» To complete the circle at top most point `T_(2)=0` `Mg-(q^(2)/(4piepsilon_(0)l^(2)))=(MV^(2))/(l)` `rArr V^(2)-g^(l)=-(q^(2))/(4piepsilon_(0)Ml)....(1)` from law of conservation of law `(1)/(2)m u^(2)=(1)/(2)mv^(2)+mg2l....(2)` from(1) and (2) `u=sqrt(4gl-(q^(2))/(4piepsilon_(0)ml))=5.86m//s` |
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