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A small ball is dropped from rest from height 10 m on a horizontal floor. If coefficient of restitution between ground and body is `0.5` then find the maximum height it can rise after collision. |
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Answer» The ballis dropped from height `h_(1)` so velocity just before hitting the ground= velocity of approach `=V_("approach"=sqrt(2gh_(1)))` The ball rises to the height `h_(2),` so velocity when just leaves the ground = velocity of sparation `=sqrt(2gh_(2))=V_("separation")` Coefficient of restitution, `e=(V_("separation"))/(V_("approach"))` `impliese=sqrt((2gh_(2))/(2gh_(1)))=sqrt((h_(2))/(h_(1)))` `impliesh_(2)=e^(2)h_(1)` `=1/4xx10=2.5m` |
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