1.

A small ball of mass m suspended from the celling at a point O by a thread of length l moves along a horizontal circle with a constant angular velocity omega. .

Answer»

linear momentum of system (BALL + rod) is conserved
angular momentum about C is conserved
kinetic energy of system (ball + rod) before the collision is equal to kinetic energy of system just after the collision
linear momentum of ball is conserved

Solution :Since ball MOVES with constant angular velocity inhorizontal circle than
(A) For angular momentum about `A`, it will have angular momentum perpendicular to `l` That will have TWO component one along `CO` which is constant and another in the plane which canges direction.
(B) Angular momentum about `C` is constant `(mvr)` along `OC`.


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