A small block of wood of specific gravity 0.5 is subnerged at a depth of 1.2 m in a vessel filled with water. The vessel is accelerated upwards with an acceleration a_(0) = (g)/(2). Time taken by the block to reach the surface, if it is released with zero initial velocity is (g = 10 m//s^(2))

A small block of wood of specific gravity 0.5 is subnerged at a depth

1.	A small block of wood of specific gravity 0.5 is subnerged at a depth of 1.2 m in a vessel filled with water. The vessel is accelerated upwards with an acceleration a_(0) = (g)/(2). Time taken by the block to reach the surface, if it is released with zero initial velocity is (g = 10 m//s^(2))
Answer» <html><body><p>0.6 s<br/>0.4 s<br/>1.2 s<br/>1 s</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>