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A small block slides without friction down an iclined plane starting form rest. Let `S_(n)` be the distance traveled from time `t = n - 1` to `t = n`. Then `(S_(n))/(S_(n + 1))` is:A. `((2n-1))/(2n)`B. `((2n+1))/((2n-1))`C. `((2n-1)/(2n+1))`D. `((2n)/(2n+1))` |
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Answer» Correct Answer - C Distance travelled in `t^(th)` second is `S_(t)=u+(a)/(2)(2t-1)` `u = 0` `S_(n)=(a)/(2)(2n-1)` `S_((n)/(n+1))=(a)/(2)[2n+1]` `(S_(n))/(S_(n+1))=((2n-1))/((2n+1))` |
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