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A small body of mass 0.10 kg is executing S.H.M. of amplitude 1.0 m and period 0.20 sec . The maximum force acting on it iA. 98.7 NB. 985.96 NC. 100.2 ND. 76.23 N |
Answer» Correct Answer - A `F=momega^(2)A` `=0.1(4pi^(2))/(T^(2))xx1` `=(0.1xx4xx9.87)/(0.04)=98.7N` |
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