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A small body of mass 0.10 kg is executing S.H.M. of amplitude 1.0 m and period 0.20 sec . The maximum force acting on it iA. 98.7 NB. 985.96 NC. 100.2 ND. 76.23 N

Answer» Correct Answer - A
`F=momega^(2)A`
`=0.1(4pi^(2))/(T^(2))xx1`
`=(0.1xx4xx9.87)/(0.04)=98.7N`


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