A small coin is kept on a horizontal platform. The platform is oscillating vertically with a time period of 0.5s. What should be the maximum amplitude of vibration so that the coin always remains in contact with the platform?

A small coin is kept on a horizontal platform. The platform is oscilla

1.	A small coin is kept on a horizontal platform. The platform is oscillating vertically with a time period of 0.5s. What should be the maximum amplitude of vibration so that the coin always remains in contact with the platform?
Answer» Solution :The coin will always remain in CONTACT with the platform if the downward acceleration of the platform does not exceed the acceleration of the coin due to gravity. If A is the maximum amplitude of VIBRATION, then `OMEGA^(2)A=g` or, `A=g/omega^(2)=g/(((2pi)/T)^(2))=(gT^(2))/(4PI^(2))` = `(9.8xx(0.5)^(2))/(4xx(3.14)^(2))=0.06205m~~0.06m`.