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A small hole of area of cross-section 2mm^(2) is present near of the bottom of a fully filled open tank of height 2m. Taking g= 10 m//s^(2), the rate of flow of water through the open hole would be nearly: |
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Answer» `6.4 XX 10^(-6) m^(3)//s` Time rate of flow of water, = AV `=A sqrt(2gh)` `=(2 xx 10^(-6)) (2 xx 10 xx 2)^(½)` `=4 sqrt10 xx 10^(-6)` `=4 xx 3.16 xx 10^(-6)` `=12.64 xx 10^(-6)` `~~ 12.6 xx 10^(-6) m^(3)//s` |
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