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InterviewSolution
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A small ink dot on a paper is viewed through a glass slab of thickness `10 cm` , and refractive index `1.5`. By what distance would the dot appear to be raised ? |
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Answer» Here, real thickness of glass slab, `x = 10 cm , mu = 1.5` If apparent thickness of glass slab is `y`, then from `mu = (x)/(y)` `y = (x)/(mu) = (10)/(1.5) = 6.67 cm` Distance through which the dot appears to be raised `= x - y = 10 - 6.67 = 3.33 cm`. |
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