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A small metal ball falls in liquid with a terminal velocity of V. If a ball of radius twice of first ball but same mass falls through a same medium, calculate the terminal velocity with which it falls. |
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Answer» Solution :Given`v = (2R^(2)rhog)/(9eta)` mass `= 3/4 pi r^(3) RHO = 4/3 pi (2r)^(3)rho_(1)`or`rho_(1) = (rho)/(8)` TERMINAL velocity of second ball is `v_(1) = (2(2r)^(2)(rho/8)G)/(9eta) = v/2` `v_(1) = v/2` |
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