A small on rough inclined groove on rough inclined plane of inclination theta. Groove makes an angle alpha as shwon in Fig . 7.173, mu is the coefficient of friction . Which of the following is correct ?

A small on rough inclined groove on rough inclined plane of inclinatio

1.	A small on rough inclined groove on rough inclined plane of inclination theta. Groove makes an angle alpha as shwon in Fig . 7.173, mu is the coefficient of friction . Which of the following is correct ?
Answer» Normal force by inclined plane . N = mg cos `theta` Normal force by inclined is `N = mg sqrt(cos^(2) theta + sin^(2) theta sin^(2) ALPHA)` Maximum frictional force that can develop is `f_("max") =MU mg cos theta` If `mu=0` then acceleration of block is g sin `theta cos alpha` Solution :`N _(1) = mg cos theta ` PERPENDICULARTO the plane `N_(2) = mg sin theta sin alpha` `N_(2)` is the plane of INCLINE perpendicular to groove . `N = sqrt(N_(1)^(2) + N_(2)^(2) ) = "If " mu = 0 ` Net force along groove is mg sin `theta cos alpha` . Hence , acceleration is g `sin theta cos alpha` .