1.

A small part of `dl` length is removed from a ring having charge per unit length `lamda`. Find electric field at centre due to remaining ring.A. zeroB. `(-lambda l)/(4 pi epsi_(0)a^(2))`C. infinityD. `(lambda)/(4 pi epsi_(0)l)`

Answer» Correct Answer - B


Discussion

No Comment Found

Related InterviewSolutions