A small particale carying a negative charge of `1.6xx10^(-19)C` ia suspended in equilibrium between the horizontal metal plates 5 cm apart, having a potential difference of 3000 V across them. Find the mass of the particle.

A small particale carying a negative charge of `1.6xx10^(-19)C` ia sus

1.	A small particale carying a negative charge of `1.6xx10^(-19)C` ia suspended in equilibrium between the horizontal metal plates 5 cm apart, having a potential difference of 3000 V across them. Find the mass of the particle.
Answer» Here, `q = -1.6xx10^(-19)C`. `dr = 5 cm = -5xx10^(-2)m, dV = 3000 V, m = ?` `E = (dV)/(dr) = (-3000)/(5xx10^(-2)) = -6xx10^(4) Vm^(-1)` As the charged particle remains suspended in equalibrium, therefore, `F = mg = qE` or `m = (qE)/(8) = (-1.6xx10^(-19)xx(-6xx10^(4)))/(9.8)` `= 9.8xx10^(-16) kg`

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A small particale carying a negative charge of `1.6xx10^(-19)C` ia suspended in equilibrium between the horizontal metal plates 5 cm apart, having a potential difference of 3000 V across them. Find the mass of the particle.

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