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A small particle of mass m//10 is moving horizontally at a height of 3R//2 from ground with velocity 10m//s. A perfectly inelastic collision occurs at point P of surface. The mass m of sphere is R. (m = 10 Kg and R = 0.1 m) (Assume all surfaces to be smooth). Answer the following questions. Speed of shpere just after collision is

Answer»

`27//43 m//s`
`(30)/(43)m//s`
`(35)/(43) m//s`
`(40)/(43) m//s`

Solution :
Let `v^(1)` be the velocity of sphere after COLLISION
`J cos 30 = 10v^(1)rArr J = (20 v^(1))/(sqrt(3))`
`J = (m)/(10)(10 cos 30)-(m)/(10)(v^(1) cos 30^(@))`
`rArr` speed of the sphere `v^(1) = (30)/(43) ms^(-1)`
speed of particle in TANGENTIAL direction remains same
`10 sin 30 = 5ms^(-1)`
speed of partile `= sqrt((5)^(2)+[((30)/(43))cos 30])^(2)`
`=5.26 ms^(-1)`


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