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A small particle of mass m//10 is moving horizontally at a height of 3R//2 from ground with velocity 10m//s. A perfectly inelastic collision occurs at point P of surface. The mass m of sphere is R. (m = 10 Kg and R = 0.1 m) (Assume all surfaces to be smooth). Answer the following questions. Speed of shpere just after collision is |
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Answer» `27//43 m//s` Let `v^(1)` be the velocity of sphere after COLLISION `J cos 30 = 10v^(1)rArr J = (20 v^(1))/(sqrt(3))` `J = (m)/(10)(10 cos 30)-(m)/(10)(v^(1) cos 30^(@))` `rArr` speed of the sphere `v^(1) = (30)/(43) ms^(-1)` speed of particle in TANGENTIAL direction remains same `10 sin 30 = 5ms^(-1)` speed of partile `= sqrt((5)^(2)+[((30)/(43))cos 30])^(2)` `=5.26 ms^(-1)` |
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