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A small piece of wire bent into L shape with upright and horizontal portions of equal length 10cm each. It is plaed with the horizontal portion along the axis of the concave mirror of focal length 10cm. if the bend is30cm from the pole. The ratio of the lengths of the images of the upright and horizontal portions of the wireis1) 1:22) 2:13) 1:14) 3:1 |
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Answer» What would you like to ask?12thPhysicsRay Optics and Optical InstrumentsProblems on Mirror and Magnification FormulaA small PIECE of wire bent ...PHYSICSA small piece of wire bent into an L shape, with UPRIGHT and horizontal portions of EQUAL lengths, is placed with the horizontal portion along the axis of the concave mirror whose radius of curvature is 10 cm. If the bend is 20 cm from the pole of the mirror,then the ratio of the lengths of the images of the upright and horizontal portions of the wire isMEDIUMShareStudy laterANSWERGiven, u=−20 ; f=−5From mirror formula, v1 + U1 = f1 v1 − 201 = 5−1 v= 3−20 magnification= u−v = 3−1 lateral magnification is (u−f) 2 f 2 = (20−5) 2 25 = 91 Ratio of up-right portion to lateral portion is 91 31 =3:1option B is correct Explanation:HERE IS YOUR ANSWER PLEASE MARK ME BRAINLIEST |
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