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A small pulse is generated on a ring rotating with constant angular velocity `omega` as shown in the figure. Then the speed of pulse with respect to ground.A. `omegaR`B. `omegaR//2`C. `2omegaR`D. zero |
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Answer» Correct Answer - D `2Tsintheta=dmomegat^(2)R` `approx2Ttheta=mudlomega^(2)R` `approx2Ttheta=muR^(2)thetaomega^(2)R` `implies(T)/(mu)omega^(2)R^(2)` or `v_(wave)=omegaR` Note `v_(wave)` obtained is always with respect to medium. `thereforev_("wave/ground")=omegaR-omegaR` `=0` |
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