1.

A small pulse is generated on a ring rotating with constant angular velocity `omega` as shown in the figure. Then the speed of pulse with respect to ground.A. `omegaR`B. `omegaR//2`C. `2omegaR`D. zero

Answer» Correct Answer - D
`2Tsintheta=dmomegat^(2)R`
`approx2Ttheta=mudlomega^(2)R`
`approx2Ttheta=muR^(2)thetaomega^(2)R`
`implies(T)/(mu)omega^(2)R^(2)`
or `v_(wave)=omegaR`
Note `v_(wave)` obtained is always with respect to medium.
`thereforev_("wave/ground")=omegaR-omegaR`
`=0`


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