1.

A small sphere falls from rest in a viscous liquid. Due to friction, heat is prodced. Find the relation between the rate of production of heat and the radius of the sphere at terminal velocity.

Answer» Viscous force on a falling sphere in a liquid `F=pietav_(T)`
where `v_(T)=(2.9)r^(2)(rho-sigma)g.eta` is terminal velocity `rho=` density of sphere `sigma=`density of liquid
Rate of production of heat `=(="power")=Fv_(T)=6pietarv_(1)^(2)`
`=6pietar[2/9(r^(2)(rho-sigma)g)/eta]^(2)=8/27(pig^(2)(rho-sigma)^(2))/etar^(5)`
clearly
`(dQ)/(dt)propr^(5)`


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