A smooth hemispherical bowl of radius R=0.1 m is rotating about its own axis (which is vertical) with an angular velocity 0. A particle of mass 10^(-2) kg on the inner surface of the bowl at an angled position theta (with vertical) is also rotating with same 'omega'. The particle is about a height 'h' from the bottom of thebowl. The value of 'theta' in temis of 'R' and h' is

A smooth hemispherical bowl of radius R=0.1 m is rotating about its ow

1.	A smooth hemispherical bowl of radius R=0.1 m is rotating about its own axis (which is vertical) with an angular velocity 0. A particle of mass 10^(-2) kg on the inner surface of the bowl at an angled position theta (with vertical) is also rotating with same 'omega'. The particle is about a height 'h' from the bottom of thebowl. The value of 'theta' in temis of 'R' and h' is
Answer» `H= R- ((G)/(omega^(2)))` `h= R- gomega^(2)` `R= h-((g)/(omega^(2)))` `R= h- g omega^(2)` ANSWER :A