1.

A soap bubble, having radius of 1mm, is blown from a detergent solution having a surface tension of 2.5 xx 10^(-2)N//m. The pressure inside the bubble equals at a point Z_(0) below the free surface of water in a container. Taking g= 10 m//s^(2), density of water =10^(3)kg//m^(3), the value of Z_(0) is

Answer»

0.5cm
100cm
10cm
1cm

Solution :Here, R=mm `=1 xx 10^(-1) CM= 1 xx 10^(-3)m`
Density of water `rho= 10^(3) kgm^(-3)`
`h= Z_(0)`
`T= 2.5 xx 10^(-2) N//m`

`G= 10 ms^(-2)`
Pressure inside the bubble, formed in air,

`P_(i) = P_(0) + (4T)/(R )= P + (4T)/(R )` ...(1) (Where P= atmospheric pressure)
If pressure at depth `Z_(0)` from the free SURFACE of water is P. then,
`P.= P + rho gh= P + rho g Z_(0)` ...(2)
Comparing equations (1) and (2), `rho g Z_(0) = (4T)/(R )`
`:. Z_(0) = (4T)/(rho gR) = (4 xx 2.5 xx 10^(-2))/(10^(3) xx 10 xx 1 xx 10^(-3))`
`:. Z_(0) = 10^(-2)m= 1cm`


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