A soap bubble is blown to a radius of 3 cm. If it is to be further blown to a radius of 4 cm what is the work done ? (Surface tension of soap solution = 3.06xx10^(-2)Nm^(-1))

A soap bubble is blown to a radius of 3 cm. If it is to be further blo

1.	A soap bubble is blown to a radius of 3 cm. If it is to be further blown to a radius of 4 cm what is the work done ? (Surface tension of soap solution = 3.06xx10^(-2)Nm^(-1))
Answer» Solution :Initial radius of the soap bubble `R_(1)=3cm=3xx10^(-2)m`. Final radius of the soap bubble `R_(2)=4cm=4xx10^(-2)m` work done in blowing a soap bubble from radius `R_(1)` to `R_(2)=W=8pi(R_(2)^(2)-R_(1)^(2))S` `=8XX(22)/(7)xx3.06xx10^(-2)(16-9)xx10^(-4)` `=176xx3.06xx10^(-6)J=539.6xx10^(-6)J`