InterviewSolution
Saved Bookmarks
| 1. |
A soap bubble is blown to a radius of 3 cm. if it is to be further blown to a radius of 4 cm what is the work done? (surface tension of soap solution `=3.06xx10^(-2)Nm^(-1))` |
|
Answer» Initial radius of soap bubble `R_(1)=3cm=3xx10^(-1)m` Final radius of soap bubble `R_(2)=4cm=4xx10^(-2)m` Wirk done in blowing soap buble from radius `R_(1)` is `R_(2)` is `impliesW=8pi(R_(2)^(2)-R_(1)^(2))T` `=8xx(22)/(7)xx3.06xx10^(-2)(16-9)xx10^(-4)` `=176xx3.06xx10^(-6)J=539.6xx10^(-6)J` |
|