A sodium salt of unknown anion when treated with MgCl_(2) gives white precipitateonly on boiling . The anion is

A sodium salt of unknown anion when treated with MgCl_(2) gives white

1.	A sodium salt of unknown anion when treated with MgCl_(2) gives white precipitateonly on boiling . The anion is
Answer» <html><body><p>`SO_(4)^(2-)`<br/>`HCO_(3)^(-)`<br/>`CO_(3)^(2-)`<br/>`NO_(3)^(-)`</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/bicarbonates-896608" style="font-weight:bold;" target="_blank" title="Click to know more about BICARBONATES">BICARBONATES</a> on heating <a href="https://interviewquestions.tuteehub.com/tag/form-996208" style="font-weight:bold;" target="_blank" title="Click to know more about FORM">FORM</a> insoluble <a href="https://interviewquestions.tuteehub.com/tag/carbonates-413333" style="font-weight:bold;" target="_blank" title="Click to know more about CARBONATES">CARBONATES</a> <br/> `MgCl_(2) + 2 NaHCO_(3) to NaCl + Mg(HCO_(3))_(2)` <br/> `Mg(HCO_(3))_(2) <a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>(Delta)(to) MgCO_(3) darr + CO_(2) + H_(2)O`</body></html>