A sodium salt on treatment with MgCl_(2) gives white precipitate on heating. The anion of the sodium salt is:

A sodium salt on treatment with MgCl_(2) gives white precipitate on he

1.	A sodium salt on treatment with MgCl_(2) gives white precipitate on heating. The anion of the sodium salt is:
Answer» <html><body><p>`CO_(3)^(2-)`<br/>`HCO_(3)^(Θ)`<br/>`SO_(4)^(2+)`<br/>`NO_(3)^(Θ)`</p>Solution :Given, `NaX+MgCl_(2)overset(Delta)(rarr)`White ppt. <br/> `NaHCO_(3)+MgCl_(2)rarrunderset("Soluble")(<a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>(HCO_(3))_(2))+NaCl` <br/> `Mg(HCO_(3))_(2)overset(Delta)(rarr)underset("White ppt".)(MgCO_(3))+H_(2)O+Co_(2)` <br/> Hence, anion of the <a href="https://interviewquestions.tuteehub.com/tag/sodium-1215510" style="font-weight:bold;" target="_blank" title="Click to know more about SODIUM">SODIUM</a> salt is `HCO_(3)^(Θ)`.</body></html>