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A sodium salt on treatment with `MgCl_(2)` gives white precipitate only on heating. The anion of the sodium salt is `:`A. `HCO_(3)^(-)`B. `CO_(2)^(2-)`C. `NO_(3)^(-)`D. `SO_(4)^(-)` |
Answer» Correct Answer - A The anion is `HCO_(3)^(-)` and it reacts with `MgCI_(2)` as follows: `2NaHCO_(3) + MgCI_(2) to Mg (HCO_(3))_(2) + 2NaCI` `Mg(HCO_(3))_(2) overset("Heat")(to) MgCO_(3) + CO_(2) + H_(2)O` |
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