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A soldier fires bullets, each of mass 50 g, from his automatic rifle with a velocity of 1000 m/s. If he can bear a maximum force of 200 N on his shoulder, find the number of bullets which he can fire in a second. |
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Answer» SOLUTION :Themomentumimparted ton bullets persecond = (nmv-0 )= nmv(momentumofa bullet=MV ) `=nmv = (DP)/(dt )` `=:. , 200nmv ` `n = (200)/( mv)= (200)/( 50 XX 10^(-3)xx 10^(3))` `:., n= 4` |
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