A soldium salt of unknown anion when treated with MgCl_(2) gives white precipitate only on boiling. The anion is:

A soldium salt of unknown anion when treated with MgCl_(2) gives white

1.	A soldium salt of unknown anion when treated with MgCl_(2) gives white precipitate only on boiling. The anion is:
Answer» <html><body><p>`SO_(4)^(2-)`<br/>`HCO_(3)^(-)`<br/>`CO_(3)^(2-)`<br/>`NO_(3)^(-)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The salt is `NaHCO_(3)` <br/> `2NaHCO_(3) + MgCl_(2) rarr underset(("White ppt"))underset(MgCO_(3))underset(darr "heat")(Mg(HCO_(3))_(2))+ 2NaCl`</body></html>