InterviewSolution
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InterviewSolution
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A solenoid of `500turns` per meter is carrying a current of `3A`. Its core is made of iron, which has a relative permeability of `5000`. Determine the magnitudes of magnetic intensity, intensity of magnetization and magnetic field inside the core. |
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Answer» Here, `n = 500` turns/m, `i = 3A, mu_(r) = 5000` Magnetic intensity, `H = n i = 500 m^(-1) xx 3A = 1500 Am^(-1)` As `mu_(r) = 1 + chi_(m)` `:. Chi_(m) = mu_(r) - 1 = 5000 - 1 = 4999 ~~ 5000` Also, `mu_(r) =(mu)/(mu_(0)) = 5000 :. mu = 5000 mu_(0)` Intensity of magnetisation, `I = chi_(m) H = 5000 xx 1500 = 7.5 xx 10^(6) Am^(-1)` Magnetic field inside the core, `B = mu H = 5000 mu_(0)H` `= 5000 (4pi xx 10^(-7)) xx 1500` `B = 3 pi = 3 xx (22)/(7) = 9.4T` |
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