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A solenoid of length `0*20m`, having `120` turns carries a current of `2*5A`. Find the magnetic field: (a) in the interior of the solenoid, (b) at one end of the solenoid. Given `mu_0=4pixx10^-7` S.I. units. |
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Answer» Correct Answer - (a) `1*885xx10^-3T` (b) `0*9425xx10^-3T` (i) `B=mu_0(NI)/(l)`, Here, `l=0*20m`, `N=120`, `I=2*5A` (ii) `B=(mu_0NI)/(2l)` |
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