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A solenoid of length `0.4m` and having `500` turns of wire carries a current of `3amp`.Calculate the torque requred to hold a coil (having radius `0.02 cm` current `2A` and turns `50`)in the middle of the solenoid with its axis perpendicular to the axis of the solenoid.`(pi^(2)=10)` |
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Answer» Correct Answer - `3/5xx10^(-7) Nm` `B=mu_(0)ni` Torque acting on the second coil `tau=M B sin 90^(@)` `=(N_(2)i_(2)A_(2))B` `=N_(2)i_(2)xxAxxmu_(0)nxxi` `tau=3/5xx10^(-7)Nm` |
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