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A solenoid of length `50cm`, having `100` turns carries a current of `2*5A`. Find the magnetic field, (a) in the interior of the solenoid, (b) at one end of the solenoid. Given `mu_0=4pixx10^-7WbA^-1m^-1`. |
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Answer» Here, `I=2*5A`, `n=100//0*50=200m^-1` (a) `B=mu_0nI=4pixx10^-7xx200xx2*5` `=6*28xx10^-4T` (b) `B=(mu_0nI)/(2)=(4pixx10^-7xx200xx2*5)/(2)` `=3*14xx10^-4T` |
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