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A solenoid of length `50cm`, having `100` turns carries a current of `2*5A`. Find the magnetic field, (a) in the interior of the solenoid, (b) at one end of the solenoid. Given `mu_0=4pixx10^-7WbA^-1m^-1`.A. `3.14 xx 10^(-4)T`B. `6.28 xx 10^(-4)T`C. `1.57 xx 10^(-4)T`D. `9.42 xx 10^(-4)T` |
Answer» Correct Answer - A Here, I = 2.5 A, l = 50 cm = 0.50 m and `n=(100)/(0.50)=200m^(-1)` `therefore" "B=(mu_(0)nI)/(2)=(4pi xx 10^(-7)xx200xx2.5)/(2)=3.14xx10^(-4)T` |
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