A solenoid of length π m and 5 cm in diameter has winding of 1000 tur

1.	A solenoid of length π m and 5 cm in diameter has winding of 1000 turns and carries a current of 5 A. Calculate the magnetic field at its centre along the axis.
Answer» Data: L = 3.142 m, N = 1000, I = 5A, μ₀ = 4π × 10^-7 T∙m/A The magnetic induction, B = μ₀ n\| = μ₀ \(\left(\cfrac{N}{L}\right)\)\| = (4π × 10^-7) \((\cfrac{1000}{3.142})(5)=\cfrac{20 \times 3.142 \times 10^{-4}}{3.142}\) = 2 × 10^-3 T

A solenoid of length π m and 5 cm in diameter has winding of 1000 turns and carries a current of 5 A. Calculate the magnetic field at its centre along the axis.

Answer»

Data: L = 3.142 m, N = 1000, I = 5A,

μ₀ = 4π × 10^-7 T∙m/A

The magnetic induction,

B = μ₀ n| = μ₀ \(\left(\cfrac{N}{L}\right)\)|

= (4π × 10^-7) \((\cfrac{1000}{3.142})(5)=\cfrac{20 \times 3.142 \times 10^{-4}}{3.142}\)

= 2 × 10^-3 T