A solid AB has CsCl type structure. The edge length of the unit cell is 404 pm. Calculate the distance of closest approach between A^+ and B^- ions?

A solid AB has CsCl type structure. The edge length of the unit cell i

1.	A solid AB has CsCl type structure. The edge length of the unit cell is 404 pm. Calculate the distance of closest approach between A^+ and B^- ions?
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Distance of closest <a href="https://interviewquestions.tuteehub.com/tag/approach-882321" style="font-weight:bold;" target="_blank" title="Click to know more about APPROACH">APPROACH</a> is <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> to the distance between the nearest neighbours (d). As <a href="https://interviewquestions.tuteehub.com/tag/cscl-410997" style="font-weight:bold;" target="_blank" title="Click to know more about CSCL">CSCL</a> has BCC lattice, <br/> `d=sqrt3/2a=1.732/2xx404` pm =349.9 pm</body></html>