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A solid `AB` has `NaCl` structure. If the radius of the cation `A` is `100` pm, what is the radius of anion `B`? |
Answer» Correct Answer - `241 pm` In `NaCl`, it has `6 : 6 CN` `:.` It has `OV`. `:. r = (r_(ɵ))/(0.414) = (100)/(0.414) = 241` pm |
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