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A solid AB has rock salt structure. If the edge length is 520 pm and radius of A+ is 80 pm, the radius of anion B– would be..........(A) 440 pm(B) 220 pm(C) 360 pm(D) 180 pm |
Answer» Correct answer is: (D) 180 pm 2r+ + 2r– = 520 \(\therefore\) \(r^++r^-=\cfrac{520}{2}\)=r-=260 – 80 = 180 pm. |
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