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InterviewSolution
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A solid consisting of a right circular cone of height 120 cm and radius 60 cm standing ona hemisphere of radius 60 cm is placed upright in a right circular cylinder full of water, suchthat it touches the bottom. Find the volume of water left in the cylinder, if the radius of thecylinder is 60 cm and its height is 180 cm. |
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Answer» We have,Radius of cylinder = Radius of cone = Radius of hemisphere = 60 cmHeight of cone = 120 cmHeight of cylindrical vessel = 120 + 60 = 180 cm Volume of cylinder =πr^2h =22/7 x(60)^2x180 Now, volume of the solid= Volume of cone + Volume of hemisphere =1/3*22/7*3600*120+2/3*22/7*60^3Volume of water left in the cylinder= Volume of the cylinder – Volume of the solid=22/7*60^2*180-1/3*22/7*60^2*120-2/3*22/7*60^3=22/7*3600(180-40-40)=7920000/7=792/700m^3 |
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