A solid cylinder of mass 2 kg and radius 50 cm rolls up an inclined plane of angle of inclination 30^(@). The centre of mass of the cylinder has speed of 4 m/s. The distance travelled by the cylinder on the inclined surface will be, [ take g=10m//s^(2)]

A solid cylinder of mass 2 kg and radius 50 cm rolls up an inclined pl

1.	A solid cylinder of mass 2 kg and radius 50 cm rolls up an inclined plane of angle of inclination 30^(@). The centre of mass of the cylinder has speed of 4 m/s. The distance travelled by the cylinder on the inclined surface will be, [ take g=10m//s^(2)]
Answer» `2.4 m` `2.2m` `1.6 m` `1.2 m` Solution :USING energy conservation we can write the FOLLOWING: `(3)/(4)MV^(2)=mghimpliesh=(3v^(2))/(4g)=(3xx(4)^(2))/(4xx10)=1.2m` Now, `(3)/(4)mv^(2)=mghimpliesh=(3v^(2))/(4g)=(3xx(4)^(2))/(4xx10)=1.2m` x=2.4 m Hence option (a) is correct.