A solid cylinder of mass 20 kg has length 1 m and radius 0.2 m. Then its moment of inertia (in kg m ) about its geometrical axis is (in kg m^2)

A solid cylinder of mass 20 kg has length 1 m and radius 0.2 m. Then i

1.	A solid cylinder of mass 20 kg has length 1 m and radius 0.2 m. Then its moment of inertia (in kg m ) about its geometrical axis is (in kg m^2)
Answer» 0.8 0.4 0.2 0.6 Solution :The MOMENT of inertia of cylinder about the geometrical AXIS = `(MR^(2))/(2) = (20 XX (0.2)^(2))/(2)= 0.4kg m^(2)`